Q) Study the following line graph and answer the questions.
Exports from Three Companies over the Years (in Rs. crore)
1)For which of the following pairs of years the total exports from the three Companies together are equal?
A)1995 and 1998
B)1996 and 1998
C)1997 and 1998
D)1995 and 1996
E)None of these
Click to View Answer
Answer D)1995 and 1996
Total exports of the three Companies X, Y and Z together, during various years are:
In 1993 = Rs. (30 + 80 + 60) crores = Rs. 170 crores.
In 1994 = Rs. (60 + 40 + 90) crores = Rs. 190 crores.
In 1995 = Rs. (40 + 60 + 120) crores = Rs. 220 crores.
In 1996 = Rs. (70 + 60 + 90) crores = Rs. 220 crores.
In 1997 = Rs. (100 + 80 + 60) crores = Rs. 240 crores.
In 1998 = Rs. (50 + 100 + 80) crores = Rs. 230 crores.
In 1999 = Rs. (120 + 140 + 100) crores = Rs. 360 crores.
Clearly, the total exports of the three Companies X, Y and Z together are same during theyears 1995 and 1996.
2) Average annual exports during the given period for Company Y is approximately what percent of the average annual exports for Company Z?
A)87.12 %
B)89.64 %
C)91.21 %
D)93.33 %
E)None of these
Click to View Answer
Answer D)93.33 %
1. The amount of exports of Company X (in crore Rs.) in the years 1993, 1994, 1995, 1996, 1997, 1998 and 1999 are 30, 60, 40, 70, 100, 50 and 120 respectively.
2. The amount of exports of Company Y (in crore Rs.) in the years 1993, 1994, 1995, 1996, 1997, 1998 and 1999 are 80, 40, 60, 60, 80, 100 and 140 respectively.
3. The amount of exports of Company Z (in crore Rs.) in the years 1993, 1994, 1995, 1996, 1997, 1998 and 1999 are 60, 90,, 120, 90, 60, 80 and 100 respectively.
Average annual exports (in Rs. crore) of Company Y during the given period
=(1/7)* (80 + 40 + 60 + 60 + 80 + 100 + 140) =560/7= 80.
Average annual exports (in Rs. crore) of Company Z during the given period
=1/7* (60 + 90 + 120 + 90 + 60 + 80 + 100) =600/7
Required percentage {80/(600/7) x 100}= % 93.33%.
3)In which year was the difference between the exports from Companies X and Y the minimum?
A)1994
B)1995
C)1996
D)1997
E)None of these
Click to View Answer
Answer C)1996
The difference between the exports from the Companies X and Y during the various years are:
In 1993 = Rs. (80 – 30) crores = Rs. 50 crores.
In 1994 = Rs. (60 – 40) crores = Rs. 20 crores.
In 1995 = Rs. (60 – 40) crores = Rs. 20 crores.
In 1996 = Rs. (70 – 60) crores = Rs. 10 crores.
In 1997 = Rs. (100 – 80) crores = Rs. 20 crores.
In 1998 = Rs. (100 – 50) crores = Rs. 50 crores.
In 1999 = Rs. (140 – 120) crores = Rs. 20 crores.
Clearly, the difference is minimum in the year 1996.
4)What was the difference between the average exports of the three Companies in 1993 andthe average exports in 1998?
A)Rs15.33 crores
B)Rs18.67 crores
C)Rs20 crores
D)Rs22.17 crores
E)None of these
Click to View Answer
Answer C)Rs. 20 crores
Average exports of the three Companies X, Y and Z in 1993
= Rs(1/3) *(30 + 80 + 60) crores = Rs170/3 crores
Average exports of the three Companies X, Y and Z in 1998
= Rs(1/3)*(50 + 100 + 80) crores = Rs230/3 crores.
Difference = Rs60/3 crores
= Rs20 crores.
5)In how many of the given years, were the exports from Company Z more than the averageannual exports over the given years?
A)2
B)3
C)4
D)5
E)None of these
Click to View Answer
Answer C)
Average annual exports of Company Z during the given period
=(1/7)* (60 + 90 + 120 + 90 + 60 + 80 + 100)
= Rs (600/7)crores = Rs. 85.71 crores.
From the analysis of graph the exports of Company Z are more than the average annualexports of Company Z (i.e., Rs. 85.71 crores) during the years 1994, 1995, 1996 and 1999,i.e., during 4 of the given years.
6)10 24 64 268 1324 ?
A)7922
B)7924
C)7964
D)7932
E) None of these
Click to View Answer
Answer c) 7964
(10 * 2 + 4) = 24
(24 * 3 – 8) = 64
(64 * 4 + 12) = 268
(268 * 5 -16) = 1324
(1324 * 6 + 20) = 7964
7)1000 992 1019 955 1080 ?
A)880
B)882
C)864
D)890
E)None of these
Click to View Answer
Answer c) 864
(1000 – 2^3) = 992
(992 + 3^3) = 1019
(1019- 4^3) = 955
(955 + 5^3) = 1080
(1080 – 6^3) = 864
8)16 18 30 60 116 206 ?
A)330
B)332
C)334
D)338
E)None of these
Click to View Answer
Answer d) 338
16 + (1^2 + 1) = 18
18 + (3^2 + 3) = 30
30 + (5^2 + 5) = 60
60 + (7^2 + 7) = 116
116 + (9^2 + 9) = 206
206 + (11^2 +11) = 338
9)92 90 172 492 1904 ?
A)9360
B)9340
C)9350
D)9456
E) None of these
Click to View Answer
Answer A) 9360
(92 – 2)*1 = 90
(90 – 4)*2 = 172
(172 – 8)*3 = 492
(492 – 16)*4 = 1904
(1904 – 32)*5 = 9360
10)26 25 26 31 42 61 ?
A)80
B)90
C)100
D)110
E)None of these
Click to View Answer
Answer B) 90
26 +(1^2 – 2) = 25
25 +(2^2 – 3) = 26
26 + (3^2 – 4) = 31
31 + ( 4^2 – 5) = 42
42 + (5^2 – 6) = 61
61 + (6^2 – 7) = 90
