I)Answer the questions based on the following information.
Some of the data missing in the table. You have to find out the remaining values based on the following facts.Half the students were either excellent or good. 40% of the students were Females. One-Third of the male students were average.
1)How many Students are both male and good?
A)23
B)22
C)20
D)24
Click to View Answer
Answer B)22
40% of the students were Females. x- Total no of students
40% of x = 32 => x = (32/40)*100 = 80
Male = 80 -32 = 48
Average male = 1/3 of Male = 1/3 of 48 = 16
Good male = Total – [Average + Good] = 48 -[16+10] = 22
Total students = 80. Half of the students = 40, As per the table Good = 30
Half the students were either Excellent or Good, Good =30 so Excellent =10, remaining Average = 40
Good Female = Total – Good Male = 30 -22 = 8
Excellent Female = Total – Good Male = 10 – 0 = 10
Students Average Good Excellent Total
Male 16 22 10 48
Female 24 8 0 32
Total 40 30 10 80
Students are both male and good = 22
2)How many Students are both female and excellent?
A)0
B)1
C)2
D)3
Click to View Answer
Answer A)0
Students Average Good Excellent Total
Male 16 22 10 48
Female 24 8 0 32
Total 40 30 10 80
Students are both female and excellent = 0
3)What is the proportion of good male students?
A)0.73
B)0.70
C)0.75
D)0.76
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Answer A)0.73
Students Average Good Excellent Total
Male 16 22 10 48
Female 24 8 0 32
Total 40 30 10 80
Good male students = 22/30 =0.73
4)Among average students, what is the ratio of male to female?
A)2:3
B)3:2
C)1:2
D)2:1
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Answer A)2:3
Students Average Good Excellent Total
Male 16 22 10 48
Female 24 8 0 32
Total 40 30 10 80
Average students – The ratio of male to female = 16:24 =2:3
5)Among Good students, what is the ratio of female to male?
A)4:11
B)11:4
C)22:15
D)15:22
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Answer A)4:11
II. Refer to the table and answer the given questions.
6)If the ratio of interest rate of E to that of D is 2:3 then what is the Principal(P) of D?
A)15000
B)20000
C)35000
D)25000
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Answer D)25000
R(%) = 4*3/2 = 6
Principal – x
x + (x*3*6/100) = 29500
x = 25000
7)If the interest is compounded yearly for three years then what is the amount to be earned by C?
A)23497.28
B)20497.28
C)22597.28
D)22697.28
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Answer E)22497.28
Amount = P(1 + (R/100)^3)
A = 20000 * 1.04 * 1.04 * 1.04
A = 22497.28
8)What is the Simple Interest(SI) of B ? If the ratio of Principal of C to that of B is 4:5 and the rate of interest is 10% more than that of C.
A)3300
B)4400
C)2200
D)1100
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Answer B)4400
P = 5/4 * 20000 = 25000
The rate of interest is 10% more than that of C.
R(%) = 4 + (4*(10/100)) = 4.4 %
SI = [25000 * 4.4 * 4]/100 = 4400
9)If the Principal(P) of A is 20% more than that of E, then What is the amount of A?
A)12694.60
B)16584.60
C)12584.80
D)12484.80
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Answer D)12484.80
Principal(P) of A = 10000 * 120/100 = 12000
A = P(1 + (R/100)^N) = 12000(1 + (2/100)^2) = 12484.80
10)If amount of D equals to five times that of his Principal then what is the Rate of Interest(%)?
A)122.22%
B)144.44%
C)133.33%
D)155.55%
Click to View Answer
Answer c)133.33%
Amount of D = Rs.29500
Principal – x
Amount of D = 5x
5x = 29500 => x= 5900
SI = 29500 – 5900 = 23600
R = 23600 * 100 / 5900 * 3 = 133.33%
