Quantitative Aptitude Quiz for IBPS | SBI | RBI – Set 242

In Quantitative Aptitude
June 13, 2017

1) The distance between A and B is 80 km. Boat P could travel from point A to B upstream and point B to A downstream in total 30 hours. Boat Q could travel from point A to B upstream and point B to A downstream in total 9 hours. If the speed of boat Q in still water is thrice of boat P in still water, what is the speed of boat Q if speed of current remains constant for both?
a) 12kmph
b) 18 kmph
c) 15 kmph
d) 20 kmph

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Answer b) 18 kmph
Let up be speed of boat P in still water, uq be speed of boat Q in still water and vp be speed of current.
According to the question,
80/?? − ?? + 80/?? + ?? = 30
80/ ?? − ?? + 80/ ?? + ?P= 9

Also it is given uq=3up, vp = vq which is already used.
Then by putting the values and solving both equation
We get speed of boat Q, uq= 18 kmph

2) A boat can travel with a speed of 16 km/hr in still water. If the rate of the stream is 5 km/hr, then what is the time taken by the boat to cover distance of 84 km downstream?
a) 1 hours
b) 4 hours
c) 5 hours
d) 2.5 hours

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Answer b) 4 hours
Speed of boat = 16 kmph
Speed of stream = 5 kmph
Downstream speed = 16+5 kmph = 21 kmph
Time take to go 84 km downstream = 84/21 = 4 hours

3)A boat takes 19 hrs for travelling downstream from point A to point B and coming back to a point C midway between A and B. if the speed of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B?
a) 180 km
b) 240 km
c) 160 km
d) 200 km

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Answer a) 180 km

Answer According to the question, Speed of boat = 14 kmph
Speed of stream = 4 kmph
Let the distance be x
Therefore upstream speed = 14-4 = 10 kmph
Downstream speed = 14+4 = 18 kmph
Then we have,
(?/2)/ 10 + ?/ 18 = 19
?? ??????? ?? ??? ? = 180 ??

4) A man row 18 kmph in still water. It takes him thrice as long as row up as to row down the river. Find the rate of stream.
a) 4/33 kmph
b) 3/34 kmph
c) 4 kmph
d) 2/27 kmph

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Answer d)2/27 kmph
Time take to row upstream (Tu) = 3 * time taken to row downstream(Td)
Speed to row upstream = 1/3 * speed taken to row downstream.
Given Tu + Td = 18
1/Su + 1/Sd = 18
Putting Su = 1/3 * Sd
We have Sd = 4/ 18 kmph
Su = 4/54 kmph
Speed of stream = (Sd-Su)/2 = 2/27 kmph

5)A boat can row 16 km/hr along the current and 14 km/hr against the current. Find the speed of the current and speed of the boat in still water?
a) 2 kmph, 15 kmph
b) 2 kmph, 12 kmph
c) 2 kmph, 32 kmph
d) 1 kmph, 15kmph

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Answer d) 1 kmph, 15kmph

Speed of boat = (speed against the current + speed in favour of current)/2 = (16+14)/2 = 15 kmph
Speed of current = (speed in favour of current _ speed against the current)/2 = (16-14)/2 = 1 kmph

Direction (Qus 6-10): Study the following table carefully and answer the given questions.

6)What is the principal of Kamal if the ratio of the rate of interest Anil to that of Kamal is 2 : 3?
a) 24500
b) 25500
c) 26000
d) 27500

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Answer c) 26000
Rate of interest of Kamal = 6 ×3/2 = 9%
Amount = 35360
Time = 4 years
Let the principal be x
Then, x + ? ×9 ×4/ 100
= x(1 + 36/100 = 35360
X ×136/100 = 35360
X = 26000

7) What is the amount of Sunil, if the interest is compounded yearly for 3 years?
a) 24385.625
b) 26900.615
c) 27500.565
d) 28940.625

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Answer d) 28940.625
Amount of Sunil = P 1 + ?/100 t
= 25000 × (1 + 5/100)^3
= 25000 ×21/20 × 21/ 20 × 21/20
= 28940.625

8)At what Rate of Interest does the amount of Kamal become 5 times his principal?
a) 95%
b) 102%
c) 98%
d) 100%

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Answer d) 100%
Let the principal be x
Then, SI = 5x – x = 4x
4x = x × r × 4/100
r = 100%

9)What will be the amount of Bilal in two years when his principal is 30% more than Anil‘s?
a) 18738.18
b) 16872.96
c) 19638.1
d) 19548.18

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Answer b) 16872.96
Principal of Bilal = 12000 × 130/100 = 15600
Amount of Bilal = 15600 × (1 + 4/100)
= 15600 ×26/25 × 26/25
= 16872.96

10) If the ratio of principal of Sunil to that of Jalal is 5 : 6 and the rate of interest of Jalal is 20% more than that of Sunil, then what is the interest of Jalal?
a) 9000
b) 8000
c) 9400
d) 7500

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Answer a) 9000
Principal of Jalal = 25000 ×6/5 = 30000
Rate of interest = 5 ×120/100 = 6%
Interest =
30000 ×6 ×5/100
= 9000

Also Check Out Quantitative Aptitude Quiz for IBPS | SBI | RBI – Set 241