Quantitative Aptitude Quiz for IBPS | SBI | RBI – Set 240

Directions (Q1-5): In the following pie-charts the percentage of different categories of employees of two companies A and B are given and the table shows the percentage of Male employees among them. The total employees in Company A is 6500 and that in Company B is 9000.

1) What is the total number of female employees of category E4 in Company A?
a) 975
b) 468
c) 507
d) 864

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Answer c) 507
Female E4= 6500*15/100* 100-48/100 = 507

2) What is the average number of male employees of all categories in Company B?
a)652
B)786
c)780
d)885

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Answer B)786

3) What is the difference between the total number of male and female employees in Company A?
a)150
B)156
c)160
d)180

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Answer c) 156
Total males 6500( 0.22 * 0.4 + 0.17 * 0.6 + 0.21 * 0.4 + 0.15 * 0.48 + 0.16 *0.55 + 0.09 * 0.6 ) 6500*0.488 = 3172
Females = 6500-3172 = 3328
difference = 3328- 3172 = 156

4) The total number of female employees in categories E1, E2 and E3 together in Company B is what percentage of the total employees in Company B?
a)28.5%
B)30.5%
c)20.5%
d)28.6%

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Answer a)28.5%

5) The total male employees of category E5 and E6 in Company B is approximately what percentage more than the total male employees of category E4 and E5 in Company A?
a)10%
B)17%
c)16%
d)12%

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Answer B)17%

Total males (E5+E6)B= 702+ 513= 1251
Total marks = (E4+E5)A = 468+572= 1040
required % = 1215- 1040 /1040 *100= 175/ 1040 *100 = 16.826% (17% )

6) A batsman average run rate was 60 runs in 50 innings. Difference between the highest and the lowest score was 180. If these two innings are not included the average of remaining 48 innings becomes 58. Find his lowest score.
a) 10 runs
b) 12 runs
c) 18 runs
d) 15 runs

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Answer c) 18 runs
Total runs = 60×50 = 3000 runs
After excluding two innings.
Total runs = 48×58 = 2784 runs
H + L = 216, and H – L = 180
Lowest (L) = 18runs

7) Work done by A in one day is 3/2 of the work done by B in one day. Work done by B is 1/2 of the work done by C in one day. If C alone can complete the work in 9 days, in how many days will A, B and C together complete the work?
a) 6 days
b) 5 days
c) 4 days
d) 10 days

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Answer c)4days
Let work done by B in one day be ‘x’
So, work done by A in one day = 3x/2
work done by C in one day = 2x
C can alone complete the work in 9 days
Total work = 9*2x = 18x
Work done by A, B and C together in one day = 3x/2 + x + 2x = 9x/2
Total days required to complete the work by them = 18x/(9x/2)= 4 days

8)A right angle triangle with height 5 cm and base 12 cm. This triangle is rotated once accordingly its heights. Find the curved surface area of the cone obtained?
a) 146 π
b) 136 π
c) 156 π
d) 166 π

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Answer c)156 π
l = √(52+122) = 13
Curved surface area = π* r * l = π* 12 * 13 =156 π

Directions (Q9-10): Each of these questions consists of a question followed by information in three statements. You have to study the question and the statements and decide that information in which of the statement(s) is/are necessary to answer the question.

9)What is the speed of a train?
I) The train crosses a pole in 12 seconds.
II) The length of the train is 350 meters.
III) The train crosses a platform double its length in 36 sec.
a) I only
b) II only
c) Either I and II together or II and III together
d) III only

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Answer c)Either I and II together or II and III together
Using Statement, I & II
Speed = 350/12 = 29.16 m/s
Using Statement, II & III
Speed = (350*2)/36=19.45 m/s

10)What is a two-digit number?I) The number obtained by interchanging the digits of the number is lesser than the original number by 27.
II) The ratio of digits of the original number is 5 : 2.
III) The difference between the two digits of the original number is 3.
a) I and II both
b) Either I and II together or II and III together
c) III only
d) I and III

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Answer b)Either I and II together or II and III together
From Statement I
(10x+y) – (10y-x) = 27
x-y = 3
From Statement II
X : y = 5 : 2
From statement III
x-y = 3
So the digit can be obtained by Either I and II together or II and III together

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