I. Missing Data in the table
Directions for questions 1 to 3 : A team of 5 players Arpit, Bimal, Chatur, Dinu and Elan participated in a ‘Freaket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match.None of the two missing values is more than 10% of the total runs scored in that match.
| Match-1 | Match-2 | Match-3 | Match-4 | ||
| Runs scored by player | Arpit | 100 | 53 | ||
| Bimal | 88 | 65 | 52 | ||
| Chatur | 110 | ||||
| Dinu | 72 | 75 | 20 | 56 | |
| Elan | 60 | 78 | |||
| Total | 270 | 300 | 240 | 200 | |
1)
What is the maximum possible percentage contribution of Arpit in the total runs scored in the four matches?
A. 19.7% B. 19.9%
C. 20.1% D. 20.2%
2)
If the absolute difference between the total runs scored by Arpit and Chatur in the four matches is minimum possible then what is the absolute difference between total runs scored by Bimal and Elan in the four matches?
A. 32 B. 37
C. 27 D. Cannot be determined
3)
The players are ranked 1 to 5 on the basis of
the total runs scored by them in the four matches, with the highest scorer getting Rank 1. If it is known that no two players scored the same number of total runs, how many players are there whose rank can be exactly determined?
A. 0 B. 1
C. 3 D. 5
II.
DIRECTIONS FOR QUESTIONS 1 to 5 :
RAILWAY TIMETABLE : NEW DELHI – BHUBANESWAR RAJDHANI EXPRESS
| Station Name | Arrival Time | Departure Time | Distance(In KM) |
| New Delhi | — | 17:05 | 0 |
| Kanpur Central | 21:48 | 21:53 | 440 |
| Mughal Sarai JN | 01:55 | 02:05 | 786 |
| Gaya JN | 04:18 | 04:21 | 989 |
| Koderma | 05:22 | 05:24 | 1066 |
| Bokaro Steel City | 07:35 | 07:40 | 1191 |
| Tatanagar JN | 10:35 | 10:40 | 1342 |
| Kharagpur JN | 12:25 | 12:40 | 1476 |
| Balasore | 14:02 | 14:04 | 1595 |
| Bhadrak | 15:12 | 15:14 | 1657 |
| Cuttack | 16:33 | 16:35 | 1772 |
| Bhubaneswar | 17:30 | — | 1800 |
1.The longest run for the train between the two successive halts is
(a) Mughal Sarai JN – Gaya JN (b) New Delhi – Kanpur Central
(c) Kanpur Central – Mughal Sarai JN (d) Balasore – Balasore
2. The average speed that the train maintained between two successive stations was the highest between
(a) Kanpur Central – Mughal Sarai JN (b) Mughal Sarai JN – Gaya JN
(c) New Delhi – Kanpur Central (d) Bokaro Steel City – Tatanagar JN
3. The average speed that the train maintained between New Delhi and Bhubaneswar was nearly equal to
(a) 72 kmph (b) 74 kmph (c) 75 kmph (d) 82 kmph
4. If we consider a journey that begins in New Delhi and ends in Bhubaneswar, the train has the longest halt at
(a) Kanpur Central (b) Mughal Sarai JN (c) Tatanagar JN (d) Kharagpur JN
5. The train begins its return journey from Bhubaneswar to New Delhi Seventeen hours after it has arrived at Bhubaneswar. If the train left New Delhi on Tuesday on what day will it have returned to New Delhi? (Assume that on the return journey that train maintains the same average speed as on the onward journey).
(a) Thursday (b) Friday (c) SaturdayAnchor (d) SundayAnchor
Answers:-
I
1)Option A
Explanation:
Maximum possible runs scored by Arpit in Match-1 = 27
Maximum possible runs scored by Arpit in Match-3 = 19
Maximum possible percentage contribution:
(27+100+19+53)/(270+300+240+200)x100% = 199/1010×100%
= 19.7%
2) Option B
Explanation:
Maximum possible total runs scored by Chatur in the four matches = 27 + 30 + 110 + 20 = 187.
In such a case minimum possible total runs scored by Arpit in the four matches = 23 + 100 + 13 + 53 = 189.
Difference = 189 – 187 = 2 (minimum possible) Subsequently total runs scored by Bimal in the four matches = 88 + 65 + 19 + 52 = 224.
Also, total runs scored by Elan in the four matches = 60 + 30 + 78 + 19 = 187
Absolute difference = 224 – 187 = 37
3)Option C
Explanation:
Individual ranges for total score:
Arpit-> 189-199
Bimal-> 218-224
Chatur-> 182-187
Dinu-> 223
Elan-> 187-188
Least total will be of Chatur (Rank 5)
2nd least will be Elan (Rank 4)
Rank 3 must be of Arpit.
It is not possible to determine the exact ranks of Bimal and Dinu.
II
| Station Name | Distance(In Km) | Time Taken(In hours) | Speed(In kmph) | |
| New Delhi – Kanpur Central | 440 | 4.72 | 93.22 | |
| Kanpur Central – Mughal Sarai JN | 346 | 4.03 | 85.86 | |
| Mughal Sarai JN – Gaya JN | 203 | 2.22 | 91.44 | |
| Gaya JN – Koderma | 77 | 1.98 | 38.89 | |
| Koderma – Bokaro Steel City | 125 | 2.18 | 57.34 | |
| Bokaro Steel City – Tatanagar JN | 151 | 2.92 | 51.71 | |
| Tatanagar JN – Kharagpur JN | 134 | 1.75 | 76.57 | |
| Kharagpur JN- Balasore | 119 | 1.37 | 86.86 | |
| Balasore – Bhadrak | 62 | 1.13 | 54.87 | |
| Bhadrak – Cuttack | 115 | 1.32 | 87.12 | |
| Cuttack – Bhubaneswar | 28 | 0.92 | 30.43 |
1)Option b
Explanation :
With the run is of 440 km, the longest run is between New Delhi – Kanpur Central.
2)Option c
Explanation :
The average speed of 93.22 kmph is the highest between New Delhi – Kanpur Central.
3)None of these
Explanation:
The average speed that the train maintained between New Delhi and Bhubaneswar = 1800 km/25 hrs and 25 min = 70.82 kmph.
4)Option d
Explanation :
The train has the longest halt of 15 minutes at Kharagpur JN.
5)Option b
Explanation :
Friday
