Quantitative Aptitude Quiz for SBI PO | IBPS | RBI – Set 109

Study the following table and answer the questions based on it.

Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.

Year Item of Expenditure
Salary Fuel and Transport Bonus Interest on Loans Taxes
1998 288 98 3.00 23.4 83
1999 342 112 2.52 32.5 108
2000 324 101 3.84 41.6 74
2001 336 133 3.68 36.4 88
2002 420 142 3.96 49.4 98

1) What is the average amount of interest per year which the company had to pay during this period?
a) Rs. 32.43 lakhs
b) Rs. 33.72 lakhs
c) Rs. 34.18 lakhs
d) Rs. 36.66 lakhs

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Answer d) Rs. 36.66 lakhs
Average amount of interest paid by the Company during the given period
= Rs.[23.4 + 32.5 + 41.6 + 36.4 + 49.4]/5 lakhs
= Rs.[183.3]/5lakhs
= Rs. 36.66 lakhs

2) The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
a) 0.1%
b) 0.5%
c) 1%
d) 1.25%

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Answer c) 1%
Required percentage = [(3.00 + 2.52 + 3.84 + 3.68 + 3.96)/(288 + 342 + 324 + 336 + 420)x 100]%
=[(17/1710) x 100] %
~= 1%.

3) Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?
a) 62%
b) 66%
c) 69%
d) 71%

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Answer c) 69%
Required percentage = [ (288 + 98 + 3.00 + 23.4 + 83) / (420 + 142 + 3.96 + 49.4 + 98) x 100 ] %
= [495.4 / 713.36 x 100 ]%
~= 69.45%.

4) The total expenditure of the company over these items during the year 2000 is?
a) Rs. 544.44 lakhs
b) Rs. 501.11 lakhs
c) Rs. 446.46 lakhs
d) Rs. 478.87 lakh

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Answer a) Rs. 544.44 lakhs
Total expenditure of the Company during 2000
= Rs. (324 + 101 + 3.84 + 41.6 + 74) lakhs
= Rs. 544.44 lakhs.

5) The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?
a) 4:7
b) 10:13
c) 15:18
d) 5:8

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Answer b) 10:13
Required ratio = [ (83 + 108 + 74 + 88 + 98) / (98 + 112 + 101 + 133 + 142) ] = [451 / 586] = 1 / 1.3
= 10 / 13

6) A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
a) 12 days
b) 15 days
c) 16 days
d) 18 days

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Answer b) 15 days
A’s 2 day’s work = (1 / 20 x 2 ) = 1 / 10
(A + B + C)’s 1 day’s work = ( 1 / 20 + 1 / 30 + 1 / 60 ) = 6 / 60 = 1 / 10
Work done in 3 days = 1 / 10 + 1 / 10 = 1 / 5
Now, 1 / 5 work is done in 3 days.
Whole work will be done in (3 x 5) = 15 days.

7) A man’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is:
a) 8.5 km/hr
b) 9 km/hr
c) 10 km/hr
d) 12.5 km/hr

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Answer c) 10 km/hr
Man’s rate in still water = (15 – 2.5) km/hr = 12.5 km/hr.
Man’s rate against the current = (12.5 – 2.5) km/hr = 10 km/hr.

8) The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
a) 23 years
b) 24 years
c) 25 years
d) None of these

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Answer a) 23 years
Let the average age of the whole team by x years.
11x – (26 + 29) = 9(x -1)
11x – 9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.

9) A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 hours to fill the tank. The leak can drain all the water of the tank in:
a) 4 1/3 hours
b) 7 hours
c) 8 hours
d) 14 hours

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Answer d) 14 hours
Work done by the leak in 1 hour = (1/2 – 3/7) = 1/14
Leak will empty the tank in 14 hrs.

10) Find the odd man out.
396, 462, 572, 427, 671, 264
a) 396
b) 427
c) 671
d) 264

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Answer b) 427
In each number except 427, the middle digit is the sum of other two.